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Class 12 Physics chapter 2 Electrostatic Potential & Capacitance important ques and Ans

CBSE Class 12 Physics chapter 2 Electrostatic Potential & Capacitance important ques and Ans

Student can find here Subject matter experts of Result4u have developed chapter wise important practice questions of CBSE Class 12 physics chapter 2 Electrostatic Potential and Capacitance as per the relevancy of the chapter in the CBSE board exam. This practice set contains 10 questions with detailed explanations on “Chapter: Electrostatic Potential and Capacitance” of Physics.

Q1.Three different capacitors are connected in series. Then:
A) They will have equal charges
B) They will have same potential
C) Both 1 & 2
D) None of these

Q2.If Q is the charge on the capacitor and E is the electric field intensity between the plates, then the force between the plates of a capacitor is
A) QE
B) 2QE
C) QE/2
D) QE/4

Q3.A hollow metal sphere of radius 10 cm is charged such that the potential on its surface is 80 volt. The potential at the centre of the sphere is:
A) 8 volt
B) 800 volt
C) 80 volt
D) Zero

Q4.The equivalent capacity of the combination shown in the figure is: (given C1 = C2 = C3 = C)
Electrostatic Potential and Capacitance
A) 2C
B) C
C) C/2
D) None of these

Q5.A regular hexagon of 0.1 m has a charge 1 μ C at each of its vertices. What is the value of electric potential at the center of the hexagon?

3 × 107V3 × 107V
2.7 × 107V2.7 × 107V
9 × 1079 × 107
None of these

Q6.What is the equivalent capacitance of the arrangement of the capacitors shown below?

Electrostatic Potential and Capacitance

3 μF3 μF
13 μF13 μF
1 μF1 μF
1.5 μF

Q7.Three capacitors each of capacity 4 µF are to be connected in such a way that the effective capacitance is 6 µF. This can be done by:

Q.8: The equivalent capacitances of Fig (1) and Fig (2) given below are:

Electrostatic Potential and Capacitance

2 μF, 1 μF2 μF, 1 μF
1 μF, 1 μF1 μF, 1 μF
1 μF, 2 μF1 μF, 2 μF
2 μF, 2 μF

Q9.If there are n capacitors each of capacitance C are connected in parallel to a voltage source of V, then the total energy stored is equal to:

CVCV
CV2CV2
12nCV212nCV2
12nCV2

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